Insert Interval

Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary).

You may assume that the intervals were initially sorted according to their start times.

Example 1:
Given intervals [1,3],[6,9], insert and merge [2,5] in as [1,5],[6,9].

Example 2:
Given [1,2],[3,5],[6,7],[8,10],[12,16], insert and merge [4,9] in as [1,2],[3,10],[12,16].

This is because the new interval [4,9] overlaps with [3,5],[6,7],[8,10].

Code in JAVA:

/**
 * Definition for an interval.
 * public class Interval {
 *     int start;
 *     int end;
 *     Interval() { start = 0; end = 0; }
 *     Interval(int s, int e) { start = s; end = e; }
 * }
 */
public class Solution {
    public static ArrayList<Interval> insert(ArrayList<Interval> intervals, Interval newInterval) {
        ArrayList<Interval> result = new ArrayList<Interval>();
  for (Interval interval: intervals) {
   if (interval.end < newInterval.start) {
    result.add(interval);
   } else if (interval.start > newInterval.end) {
    result.add(newInterval);
    newInterval = interval;
   } else if (interval.end >= newInterval.start || interval.start <= newInterval.end) {
    newInterval = new Interval(Math.min(interval.start, newInterval.start), 
             Math.max(newInterval.end, interval.end));
   }
  }
  result.add(newInterval);
  return result;
    }
}